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@ -2180,7 +2180,7 @@ Egli-Milner relator is not sound or complete, although its symmetrization is sou
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\forall x\in S,\exists y\in T, f(x)=g(y),\\
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\forall y\in T,\exists x\in S, f(x)=g(y).
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\end{gather*}
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Equivalently, $Im(f)=Im(g)$, and we call images $U$ that is in $\powf Z$. So, we equivalently have
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Equivalently, $Im(f\mid_S)=Im(g\mid_T)$, and we call images $U$ that is in $\powf Z$. So, we equivalently have
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\begin{align*}
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S\;\powf f\;U,\; T\;\powf g\;U&\\
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&\iff S\;\powf f\;U,\; U\;(\powf g)^\op\;T\\
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